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The question things with application of derivatives. Doubtnut helps with homework, doubts and solutions to all the questions. What is the maximum possible product for a set of numbers, given that they add to 10? We would like to find where the product.
Now equate the first derivative to zero be her S -2. Doubtnut is the perfect NEET and IIT JEE preparation App. So the way we do that is take the derivative with respect to X. You have to find first a function to represent the problem stated, and then find a maximum of that function. Find two positive numbers satisfying the given sum is 120 and the product is a maximum. This is something I've been investigating on my own, based on a similar question I saw elsewhere: -. We can rearrange and right, why equals S minus X and then substitute that into F of X. Y. Now we want to maximize F of X. The sum is $S$ and the product is a maximum. Now we compute B double derivative pw dash off X is equals to minus two which is less than zero. The numbers must be real and positive, but [and this was not allowed in the other versions I saw] they do not need to be integers or even rational. NCERT solutions for CBSE and other state boards is a key requirement for students. I hope you find this answer useful. Create an account to get free access.
So we now have a one-variable function. This implies that X is equals to S by two. The solution is then. Try Numerade free for 7 days. Get solutions for NEET and IIT JEE previous years papers, along with chapter wise NEET MCQ solutions. And we want that to equal zero. Now substitute the value of life from equation to such that P of X is equals to X times as minus X is equals to S X minus x. Such time productive maximized. We want to find when the derivative would be zero. That means the product is maximum, then X is equals to spy two. By clicking Sign up you accept Numerade's Terms of Service and Privacy Policy.
So what we can do here is first get X as a function of Y and S. Or alternatively Y is a function of X. It was a fun problem for me to work on, and other people who haven't seen it before might enjoy it. Now the second derivative. We'd have then that F of just X now is going to be X times actually was a capitalist, their X times s minus X or fx equals X S minus x squared. It has helped students get under AIR 100 in NEET & IIT JEE.
And s fact, I'll do that. So positive numbers. Now we have to maximize the product. 1 Study App and Learning App with Instant Video Solutions for NCERT Class 6, Class 7, Class 8, Class 9, Class 10, Class 11 and Class 12, IIT JEE prep, NEET preparation and CBSE, UP Board, Bihar Board, Rajasthan Board, MP Board, Telangana Board etc. But we also know that. Now, product of these two numbers diluted by API is equals to X times Y. I assume this is probably a previously solved problem that I haven't been able to track down, but posting it here might be good for two reasons. Get 5 free video unlocks on our app with code GOMOBILE. Math Image Search only works best with zoomed in and well cropped math screenshots.
Get PDF and video solutions of IIT-JEE Mains & Advanced previous year papers, NEET previous year papers, NCERT books for classes 6 to 12, CBSE, Pathfinder Publications, RD Sharma, RS Aggarwal, Manohar Ray, Cengage books for boards and competitive exams. Finding Numbers In find two positive numbers that satisfy the given requirements. 31A, Udyog Vihar, Sector 18, Gurugram, Haryana, 122015. According to the question the thumb is denoted by S. That is expressed by Let us name this as equation one now isolate the value of Y. Y is equals two S minus X. Get all the study material in Hindi medium and English medium for IIT JEE and NEET preparation.
Maximizing the product of addends with a given sum. So to conclude the value obtained about we have b positive numbers mm hmm X-plus y by two and X plus by by two.